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Nord | |
Altitude | 16 mètres |
Coordonnées | 50,69°N | 2,88°E |
Début des archives | 15 septembre 2008 |
Dernier report | 9 mai 2024, 11h00 |
Type de station | Réseau StatIC |
Propriétaire | Armentières59 |
Heure locale
access_time
10mn
|
Pluie | Humidité | Bio-météo | Pression |
---|---|---|---|---|
02h00 | 0 mm/1h | 87% | 1027hPa = | |
01h30 | 86% | 1027.1hPa | ||
01h00 | 0 mm/1h | 86% | 1027.1hPa | |
00h30 | 85% | 1027.0hPa | ||
00h00 | 0 mm/1h | 84% | 1027.0hPa | |
23h30 | 83% | 1027.0hPa | ||
23h00 | 0 mm/1h | 82% | 1027.0hPa | |
22h30 | 80% | 1027.0hPa | ||
22h00 | 0 mm/1h | 80% | 1027.0hPa | |
21h30 | 78% | 1027.0hPa | ||
21h00 | 0 mm/1h | 76% | 1026.8hPa | |
20h30 | 73% | 9 | 1026.6hPa | |
20h00 | 0 mm/1h | 69% | 16 | 1026.6hPa |
19h30 | 66% | 53 | 1026.5hPa | |
19h00 | 0 mm/1h | 63% | 79 | 1026.4hPa |
18h30 | 64% | 100 | 1026.4hPa | |
18h00 | 0 mm/1h | 61% | 151 | 1026.4hPa |
17h30 | 63% | 153 | 1026.6hPa | |
17h00 | 0 mm/1h | 64% | 116 | 1026.8hPa |
16h30 | 62% | 128 | 1027.0hPa | |
16h00 | 0 mm/1h | 60% | 146 | 1027.1hPa |
15h30 | 55% | 1 221 | 1027.2hPa | |
15h00 | 0 mm/1h | 47% | 185 | 1027.2hPa |
14h30 | 47% | 1 232 | 1027.3hPa | |
14h00 | 0 mm/1h | 45% | 1 281 | 1027.4hPa |
13h30 | 41% | 1 223 | 1027.5hPa | |
13h00 | 0 mm/1h | 43% | 2 773 | 1027.8hPa |
12h30 | 47% | 2 698 | 1028.1hPa | |
12h00 | 0 mm/1h | 52% | 1 679 | 1028.3hPa |
11h30 | 60% | 1 621 | 1028.5hPa | |
11h00 | 0 mm/1h | 66% | 1 566 | 1028.5hPa |
10h30 | 71% | 1 499 | 1028.5hPa | |
10h00 | 0 mm/1h | 75% | 425 | 1028.5hPa |
09h30 | 81% | 151 | 1028.4hPa | |
09h00 | 0 mm/1h | 84% | 47 | 1028.4hPa |
08h30 | 86% | 37 | 1028.4hPa | |
08h00 | 0 mm/1h | 88% | 28 | 1028.2hPa |
07h30 | 88% | 18 | 1028.0hPa = | |
07h00 | 0 mm/1h | 88% | 5 | 1028.0hPa = |
06h30 | 88% | 1027.9hPa | ||
06h00 | 0 mm/1h | 89% | 1027.8hPa | |
05h30 | 89% | 1027.8hPa | ||
05h00 | 0 mm/1h | 88% | 1027.9hPa | |
04h30 | 88% | 1027.9hPa = | ||
04h00 | 0 mm/1h | 88% | 1028.0hPa = | |
03h30 | 87% | 1028.0hPa = | ||
03h00 | 0 mm/1h | 87% | 1028.2hPa = | |
02h30 | 87% | 1028.4hPa = | ||
02h00 | 0 mm/1h | 86% | 1028.7hPa = |
Ensoleillement
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3h 50min
|
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Cumul maxi en 1h 0h-0h UTC |
0mm
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Cumul du jour 6h à 6h(J+1) |
0mm
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