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Nord | |
Altitude | 16 mètres |
Coordonnées | 50,69°N | 2,88°E |
Début des archives | 15 septembre 2008 |
Dernier report | 14 avril 2024, 20h20 |
Type de station | Réseau StatIC |
Propriétaire | Armentières59 |
Heure locale
access_time
10mn
|
Pluie | Humidité | Bio-météo | Pression |
---|---|---|---|---|
02h00 | 0 mm/1h | 77% | 1021hPa = | |
01h30 | 75% | 1021.1hPa | ||
01h00 | 0 mm/1h | 75% | 1020.9hPa | |
00h30 | 73% | 1020.9hPa | ||
00h00 | 0 mm/1h | 71% | 1020.9hPa | |
23h30 | 70% | 1020.9hPa | ||
23h00 | 0 mm/1h | 65% | 1020.8hPa | |
22h30 | 62% | 1020.7hPa | ||
22h00 | 0 mm/1h | 59% | 1020.6hPa | |
21h30 | 55% | 1020.4hPa | ||
21h00 | 0 mm/1h | 51% | 5 | 1020.1hPa |
20h30 | 48% | 16 | 1020.0hPa | |
20h00 | 0 mm/1h | 45% | 30 | 1019.7hPa |
19h30 | 43% | 46 | 1019.6hPa = | |
19h00 | 0 mm/1h | 44% | 130 | 1019.6hPa = |
18h30 | 46% | 200 | 1019.6hPa | |
18h00 | 0 mm/1h | 45% | 346 | 1019.5hPa |
17h30 | 45% | 1 473 | 1019.6hPa | |
17h00 | 0 mm/1h | 46% | 1 557 | 1019.6hPa |
16h30 | 51% | 1 508 | 1019.6hPa | |
16h00 | 0 mm/1h | 50% | 1 285 | 1019.6hPa |
15h30 | 52% | 1 234 | 1019.5hPa | |
15h00 | 0 mm/1h | 55% | 2 891 | 1019.4hPa = |
14h30 | 55% | 1 174 | 1019.3hPa | |
14h00 | 0 mm/1h | 58% | 1 188 | 1019.2hPa = |
13h30 | 65% | 1 179 | 1019.2hPa | |
13h00 | 0.5 mm/1h | 72% | 1 844 | 1019.3hPa |
12h30 | 0.2 mm/10mn 6.1mm/h | 69% | 1 185 | 1019.4hPa |
12h00 | 0 mm/1h | 63% | 1 193 | 1019.4hPa |
11h30 | 56% | 1 905 | 1019.2hPa | |
11h00 | 0 mm/1h | 58% | 1 357 | 1019.2hPa |
10h30 | 68% | 1 668 | 1019.1hPa | |
10h00 | 0 mm/1h | 79% | 1 578 | 1019.0hPa |
09h30 | 87% | 107 | 1018.9hPa | |
09h00 | 0 mm/1h | 92% | 167 | 1018.7hPa |
08h30 | 92% | 53 | 1018.6hPa | |
08h00 | 0 mm/1h | 91% | 58 | 1018.4hPa |
07h30 | 91% | 33 | 1018.0hPa | |
07h00 | 0 mm/1h | 91% | 12 | 1017.8hPa |
06h30 | 90% | 1017.5hPa | ||
06h00 | 0 mm/1h | 90% | 1017.2hPa | |
05h30 | 89% | 1017.0hPa | ||
05h00 | 0 mm/1h | 88% | 1016.7hPa | |
04h30 | 88% | 1016.6hPa = | ||
04h00 | 0 mm/1h | 88% | 1016.4hPa = | |
03h30 | 88% | 1016.3hPa = | ||
03h00 | 0 mm/1h | 87% | 1016.3hPa = | |
02h30 | 86% | 1016.2hPa = | ||
02h00 | 0 mm/1h | 85% | 1016.2hPa = |
Ensoleillement
|
4h 10min
|
|
Cumul maxi en 1h 0h-0h UTC |
0.5mm
|
|
Cumul du jour 6h à 6h(J+1) |
0.5mm
|